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efficiency of solar energy?

Just to make sure I understand this thing of solar energy: 1. Solar constant peak on the surface of the Earth = 1 kW / meter 2. Photovoltaic efficiency = 20% 3. Intermittency efficiency = 20% (this is the ratio of peak to average unit time, a total of between day and night, good and bad weather, summer and winter) 4. Storage efficiency = 25% (storage efficiency comes in two parts: the losses inflicted by putting power in storage and the losses inflicted to take place. Assume a 50% in both cases.) So we end up with 1000 kW / m * .2 * .2 * .25 = 10 watts of a meter square. I'm not saying this is good or bad. I'm just wondering if it is correct.

The photovoltaic efficiency must be less than 20% for a practical system. The most expensive of widely distributed cells, SunPower, have an efficiency of 22% maybe. Put them under glass in a practical framework, and it is up to 19%. It is $ 7 per watt type panels. Panels of $ 4 per watt than most people will install 13-15% efficiency, then puts them into a framework of practice. 36% for the type of cells from Spectrolab places like $ 250 watts are not – proprietors. Intermittency of efficiency is good for a place like California. What are you saying that 20% is what you are expecting 24 x .2 = 4.8 equivalent full sun hours about a year. This number should be higher in Southern Cal or Arizona, lower Michigan. In reality, this number can be normalization factor taking into account all other aspects of the area – the atmospheric transparency because of altitude, pollution, the operating temperature. For storage efficiency, I think you can get better than 25%. I use 70% – 80% for the battery and 95% for the investor, if any. Now for the real-life number in our system (see link below): 6556 (kWh / year) / 8765 (hours / year) / 12.5 (square meters of panel) = 60W / m ^ 2 or so. We are connected to the network without loss of the battery.

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